The reading of the ammeter in the following c | vedclass

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(D) In the given circuit,the two resistors of $60 \ \Omega$ and $40 \ \Omega$ are connected in parallel across the $6 \ V$ battery.For a parallel comb

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$0.25$

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(D) In the given circuit,the two resistors of $60 \ \Omega$ and $40 \ \Omega$ are connected in parallel across the $6 \ V$ battery.For a parallel combination,the equivalent resistance $R_{eq}$ is given by:$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} = \frac{1}{60} + \frac{1}{40}$$\frac{1}{R_{eq}} = \frac{2 + 3}{120} = \frac{5}{120} = \frac{1}{24}$So,$R_{eq} = 24 \ \Omega$.The ammeter is connected in series with the parallel combination,so it measures the total current $I$ drawn from the battery.Using Ohm's law,$I = \frac{V}{R_{eq}} = \frac{6 \ V}{24 \ \Omega} = 0.25 \ A$.

The reading of the ammeter in the following circuit is ................... $A$ (Assuming an ideal ammeter).

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