The mean deviation from the arithmetic mean o | vedclass

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(B) Given observations are $2, 7, 5, 6, 4, 3, 11, 17, 8$.First,calculate the arithmetic mean $(\bar{x})$:$\bar{x} = \frac{2 + 7 + 5 + 6 + 4 + 3 + 11 +

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$\frac{10}{3}$

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(B) Given observations are $2, 7, 5, 6, 4, 3, 11, 17, 8$.First,calculate the arithmetic mean $(\bar{x})$:$\bar{x} = \frac{2 + 7 + 5 + 6 + 4 + 3 + 11 + 17 + 8}{9} = \frac{63}{9} = 7$.Now,calculate the absolute deviations $d_i = |x_i - \bar{x}|$ for each observation:$|2 - 7| = 5$$|7 - 7| = 0$$|5 - 7| = 2$$|6 - 7| = 1$$|4 - 7| = 3$$|3 - 7| = 4$$|11 - 7| = 4$$|17 - 7| = 10$$|8 - 7| = 1$Sum of deviations $\Sigma d_i = 5 + 0 + 2 + 1 + 3 + 4 + 4 + 10 + 1 = 30$.Mean deviation ($M$.$D$.) = $\frac{\Sigma d_i}{N} = \frac{30}{9} = \frac{10}{3}$.

$x_i$	$6$	$12$	$18$	$24$	$30$	$36$	$42$
$f_i$	$4$	$7$	$9$	$18$	$15$	$10$	$5$

Height in $cm$	Number of boys
$95-105$	$9$
$105-115$	$13$
$115-125$	$26$
$125-135$	$30$
$135-145$	$12$
$145-155$	$10$

The mean deviation from the arithmetic mean of the discrete data $2, 7, 5, 6, 4, 3, 11, 17, 8$ is

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