The mean deviation about the mean for the fol | vedclass

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(B) Step $1$: Calculate the mean $(\bar{x})$: $\bar{x} = \frac{5+6+7+8+6+9+13+12+15}{9} = \frac{81}{9} = 9$ Step $2$: Calculate the mean deviation abo

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$2.88$

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(B) Step $1$: Calculate the mean $(\bar{x})$: $\bar{x} = \frac{5+6+7+8+6+9+13+12+15}{9} = \frac{81}{9} = 9$ Step $2$: Calculate the mean deviation about the mean using the formula $\frac{\sum |x_i - \bar{x}|}{N}$: $|5-9| + |6-9| + |7-9| + |8-9| + |6-9| + |9-9| + |13-9| + |12-9| + |15-9|$ $= 4 + 3 + 2 + 1 + 3 + 0 + 4 + 3 + 6 = 26$ Step $3$: Divide by the total number of observations $(N=9)$: $	ext{Mean Deviation} = \frac{26}{9} \approx 2.88$

Income per day	Number of persons
$0-100$	$4$
$100-200$	$8$
$200-300$	$9$
$300-400$	$10$
$400-500$	$7$
$500-600$	$5$
$600-700$	$4$
$700-800$	$3$

$\text{Marks}$	$10$	$15$	$20$	$25$	$30$
$\text{Number of students}$	$2$	$4$	$6$	$8$	$5$

The mean deviation about the mean for the following data: $5, 6, 7, 8, 6, 9, 13, 12, 15$ is

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Find the mean deviation about the mean for the following data:
Income per day Number of persons
$0-100$ $4$
$100-200$ $8$
$200-300$ $9$
$300-400$ $10$
$400-500$ $7$
$500-600$ $5$
$600-700$ $4$
$700-800$ $3$

The mean deviation from the mean of the data given below is
$\text{Marks}$ $10$ $15$ $20$ $25$ $30$
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Find the mean deviation about the mean for the data $38, 70, 48, 40, 42, 55, 63, 46, 54, 44$.

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