The maximum wavelength of radiation that can ionise a sodium atom is $2414 \ \mathring{A}$. The ionisation energy of sodium per mole shall be

  • A
    $241.4 \ J \ mol^{-1}$
  • B
    $497.7 \ J \ mol^{-1}$
  • C
    $241.4 \ kJ \ mol^{-1}$
  • D
    $497.7 \ kJ \ mol^{-1}$

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Based on the equation $\Delta E = - 2.0 \times 10^{-18} \, J \left( \frac{1}{n_2^2} - \frac{1}{n_1^2} \right)$,the wavelength of the light that must be absorbed to excite a hydrogen electron from level $n = 1$ to level $n = 2$ will be: $(h = 6.625 \times 10^{-34} \, J \, s, c = 3 \times 10^8 \, m \, s^{-1})$

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