The maximum velocity of the photoelectron emitted by the metal surface is $V$. The charge and mass of the photoelectron are denoted by $e$ and $m$,respectively. The stopping potential in volts is:
- A$\frac{V^2}{2(m/e)}$
- B$\frac{m V^2}{2 e}$
- C$\frac{V^2}{(e/m)}$
- D$\frac{V^2}{(m/e)}$
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