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(D) The energy of an electron in a hydrogen-like atom is given by the formula $E_n = -\frac{13.6 Z^2}{n^2} 	ext{ eV}$.As the principal quantum number

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at infinite distance from the nucleus

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(D) The energy of an electron in a hydrogen-like atom is given by the formula $E_n = -\frac{13.6 Z^2}{n^2} 	ext{ eV}$.As the principal quantum number $n$ increases,the value of $E_n$ becomes less negative,which means the energy increases.As $n 	o \infty$,the energy $E_n$ approaches $0$,which is the maximum possible energy for a bound electron.Therefore,an electron possesses maximum energy when it is at an infinite distance from the nucleus.

The maximum energy is possessed by an electron when it is present:

Similar Questions

In the hydrogen spectrum,if an electron transitions from the $6^{th}$ orbit to the $3^{rd}$ orbit through multiple steps,what is the total number of spectral lines in the $U.V.$ region?

In a hydrogen atom,if an electron transitions from an $n$-th orbit to the ground state,and the total number of spectral lines observed is $10$,then the value of $n$ is:

Explain the hydrogen spectrum using Bohr's model.

If the potential energy of an electron in a hydrogen atom is $-3.02 \ eV$,then the electron is present in which of the following excited states?

Choose the correct option regarding: Assertion: Energy of the orbital decreases with increase of $n$.
Reason: Energy is required in shifting away the negatively charged electron from the positively charged nucleus.

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