The maximum covalency and highest oxidation s | vedclass

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(C) The electronic configuration of the element with $Z=13$ (Aluminum) is $[Ne] 3s^2 3p^1$.The maximum covalency of an element is determined by the nu

Vedclass · Accepted Answer

$6, +3$

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(C) The electronic configuration of the element with $Z=13$ (Aluminum) is $[Ne] 3s^2 3p^1$.The maximum covalency of an element is determined by the number of bonds it can form using its valence orbitals. For $Al$,it can expand its octet using vacant $3d$ orbitals to form complexes like $[AlF_6]^{3-}$,resulting in a maximum covalency of $6$.Since the valence shell configuration is $3s^2 3p^1$,the element has $3$ valence electrons. Therefore,the highest oxidation state it can exhibit is $+3$.

The maximum covalency and highest oxidation state possible for an element with $Z=13$ are respectively.

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