The mass of the proton is $1840$ times that of an electron. If a proton is accelerated through a potential difference of $1 \,kV$,the kinetic energy of the proton would be

  • A
    $1 \,eV$
  • B
    $1 \,keV$
  • C
    $1840 \,eV$
  • D
    $1840 \,keV$

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The mass of the proton is $1840$ times that of the electron. If the potential difference applied is $V$,the kinetic energy of the proton is ............ $KeV$.

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