The mass of { }_7 N ^{15} is 15.00011 amu,th | vedclass

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(D) The binding energy of the last proton (also known as the proton separation energy) is given by the mass defect of the reaction: ${ }_8 O ^{16} \ri

Vedclass · Accepted Answer

$12.13$

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(D) The binding energy of the last proton (also known as the proton separation energy) is given by the mass defect of the reaction: ${ }_8 O ^{16} ightarrow { }_7 N ^{15} + { }_1 H ^1$.The mass defect $\Delta m$ is calculated as:$\Delta m = [M({ }_7 N ^{15}) + m_p] - M({ }_8 O ^{16})$Substituting the given values:$\Delta m = 15.00011 \ amu + 1.00783 \ amu - 15.99492 \ amu$$\Delta m = 16.00794 \ amu - 15.99492 \ amu = 0.01302 \ amu$Since $1 \ amu = 931.5 \ MeV/c^2$,the binding energy $E$ is:$E = 0.01302 	imes 931.5 \ MeV \approx 12.13 \ MeV$.

The mass of ${ }_7 N ^{15}$ is $15.00011 \ amu$,the mass of ${ }_8 O ^{16}$ is $15.99492 \ amu$,and $m_p = 1.00783 \ amu$. Determine the binding energy of the last proton of ${ }_8 O ^{16}$ in $MeV$.

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