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(A) For element $X$: Mass number $A = 52$. Let the number of protons be $p$. Number of neutrons $n = p + 0.166p = 1.166p$. Since $A = p + n$,we have $

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${ }_{24} Cr, { }_{33} As$

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(A) For element $X$: Mass number $A = 52$. Let the number of protons be $p$. Number of neutrons $n = p + 0.166p = 1.166p$. Since $A = p + n$,we have $52 = p + 1.166p = 2.166p$. Thus,$p = 52 / 2.166 \approx 24$. The element with atomic number $24$ is $Cr$.For element $Z$: Mass number $A = 75$. Let the number of protons be $p'$. Number of neutrons $n' = p' + 0.273p' = 1.273p'$. Since $A = p' + n'$,we have $75 = p' + 1.273p' = 2.273p'$. Thus,$p' = 75 / 2.273 \approx 33$. The element with atomic number $33$ is $As$.

The mass numbers of two elements $X$ and $Z$ are $52$ and $75$ respectively. $X$ contains $16.6 \%$ more neutrons compared to protons. $Z$ contains $27.3 \%$ more neutrons compared to protons. $X$ and $Z$ are respectively

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