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(B) The energy liberated is given by Einstein's mass-energy equivalence formula: $E = \Delta m c^2$.Given mass defect $\Delta m = 0.4 \,g = 0.4 	imes

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(B) The energy liberated is given by Einstein's mass-energy equivalence formula: $E = \Delta m c^2$.Given mass defect $\Delta m = 0.4 \,g = 0.4 	imes 10^{-3} \,kg$ and speed of light $c = 3 	imes 10^8 \,m/s$.Substituting the values: $E = (0.4 	imes 10^{-3} \,kg) 	imes (3 	imes 10^8 \,m/s)^2$.$E = 0.4 	imes 10^{-3} 	imes 9 	imes 10^{16} \,J = 3.6 	imes 10^{13} \,J$.We know that $1 \,kWh = 3.6 	imes 10^6 \,J$,so $1 \,J = \frac{1}{3.6 	imes 10^6} \,kWh$.$E = \frac{3.6 	imes 10^{13}}{3.6 	imes 10^6} \,kWh = 10^7 \,kWh$.Comparing this with $n 	imes 10^7 \,kWh$,we get $n = 1$.

The mass defect in a particular reaction is $0.4 \,g$.
The amount of energy liberated is $n \times 10^7 \,kWh$,where $n =$ . . . . . . . (speed of light $= 3 \times 10^8 \,m/s$)

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The mass defect in a particular reaction is $0.4 \,g$.The amount of energy liberated is $n \times 10^7 \,kWh$,where $n =$ . . . . . . . (speed of light $= 3 \times 10^8 \,m/s$)