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(B) The acceleration due to gravity $g$ on the surface of a planet is given by $g = \frac{GM}{R^2}$,where $M$ is the mass and $R$ is the radius of the

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$4.9$

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(B) The acceleration due to gravity $g$ on the surface of a planet is given by $g = \frac{GM}{R^2}$,where $M$ is the mass and $R$ is the radius of the planet.Given that the mass of the planet $M' = 2M$ and the diameter $D' = 2D$,which implies the radius $R' = 2R$.The acceleration due to gravity on the planet's surface $g'$ is given by $g' = \frac{GM'}{(R')^2}$.Substituting the given values: $g' = \frac{G(2M)}{(2R)^2} = \frac{2GM}{4R^2} = \frac{1}{2} \left( \frac{GM}{R^2} \right) = \frac{g}{2}$.Since $g = 9.8 \ m/s^2$ for Earth,we have $g' = \frac{9.8}{2} = 4.9 \ m/s^2$.

The mass and diameter of a planet have twice the value of the corresponding parameters of Earth. Acceleration due to gravity on the surface of the planet is ........ $m/s^2$.

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