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(A) The reaction of an alkene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. The $Br^-$ ion then attacks the bromonium

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(A) The reaction of an alkene with $Br_2$ proceeds via the formation of a cyclic bromonium ion intermediate. The $Br^-$ ion then attacks the bromonium ion from the side opposite to the bridged bromine atom,resulting in anti-addition. For the given alkene,$CH_3-CH=CH-C_2H_5$ (pent$-2-$ene),the anti-addition of $Br_2$ leads to the formation of a pair of enantiomers as the major products. These are represented by the structures in options $A$ and $D$ (or equivalent representations of the enantiomeric pair).

The major products obtained in the following reaction is/are:
$CH_3-CH=CH-C_2H_5 + Br_2 \rightarrow ?$

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The major products obtained in the following reaction is/are: $CH_3-CH=CH-C_2H_5 + Br_2 \rightarrow ?$