The major products P and Q from the following | vedclass

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Question

(A) The reaction of benzamide $(C_6 H_5 CONH_2)$ with $LiAlH_4$ followed by hydrolysis is a reduction reaction that converts the amide group $(-CONH_2

Vedclass · Accepted Answer

$P=C_6 H_5 CH_2 NH_2 \quad ; \quad Q=C_6 H_5 NH_2$

Vedclass · Answer

(A) The reaction of benzamide $(C_6 H_5 CONH_2)$ with $LiAlH_4$ followed by hydrolysis is a reduction reaction that converts the amide group $(-CONH_2)$ into an amine group $(-CH_2 NH_2)$. Thus,$P$ is benzylamine $(C_6 H_5 CH_2 NH_2)$.The reaction of benzamide $(C_6 H_5 CONH_2)$ with $Br_2 / NaOH$ is the Hofmann bromamide degradation reaction,which converts an amide into a primary amine with one carbon atom less. Thus,$Q$ is aniline $(C_6 H_5 NH_2)$.Therefore,$P = C_6 H_5 CH_2 NH_2$ and $Q = C_6 H_5 NH_2$.

The major products $P$ and $Q$ from the following reactions are:

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