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(C) The reaction of benzene with $n$-propyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts alkylation. Due to the rearrangement of the prima

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(C) The reaction of benzene with $n$-propyl chloride in the presence of $AlCl_3$ is a Friedel-Crafts alkylation. Due to the rearrangement of the primary carbocation $(CH_3CH_2CH_2^+)$ to a more stable secondary carbocation $(CH_3CH^+CH_3)$,the major product $P$ formed is isopropylbenzene (cumene). In the second step,cumene undergoes oxidation with $O_2$ followed by acid hydrolysis $(H_3O^+)$ to form phenol and acetone $(CH_3COCH_3)$ as the major products. Thus,$P$ is isopropylbenzene and $Q$ is acetone.

The major products $P$ and $Q$ are

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