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(C) The reaction sequence is as follows:$1$. Chlorination of propane $(CH_3CH_2CH_3)$ with $Cl_2$ in the presence of light $(hv)$ gives $1$-chloroprop

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$CH_2=CHCH_2OH$

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(C) The reaction sequence is as follows:$1$. Chlorination of propane $(CH_3CH_2CH_3)$ with $Cl_2$ in the presence of light $(hv)$ gives $1$-chloropropane as the major product: $CH_3CH_2CH_3 + Cl_2 \xrightarrow{hv} CH_3CH_2CH_2Cl + HCl$.$2$. Dehydrohalogenation of $1$-chloropropane with alcoholic $KOH$ gives propene: $CH_3CH_2CH_2Cl \xrightarrow{	ext{alc. } KOH} CH_3CH=CH_2 + KCl + H_2O$.$3$. High-temperature chlorination of propene $(773 \ K)$ leads to allylic substitution,forming allyl chloride: $CH_3CH=CH_2 + Cl_2 \xrightarrow{773 \ K} ClCH_2CH=CH_2 + HCl$.$4$. Nucleophilic substitution of the allylic chloride with aqueous $AgOH$ (or $NaOH$) replaces the $Cl$ atom with an $OH$ group to form allyl alcohol: $ClCH_2CH=CH_2 + AgOH_{(aq)} \longrightarrow HOCH_2CH=CH_2 + AgCl$.

The major product of the following synthetic reactions is

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