The major product of the following reaction is: $CH_3-CH_2-CH(Br)-CH_2-Br \xrightarrow[(ii) NaNH_2 \text{ in liq. } NH_3]{(i) KOH \text{ alc.}}$

  • A
    $CH_3-CH=C=CH_2$
  • B
    $CH_3-CH_2-CH(NH_2)-CH_2-NH_2$
  • C
    $CH_3-CH=CH-CH_2-NH_2$
  • D
    $CH_3-CH_2-C \equiv CH$

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