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(C) The reaction proceeds in two steps:$1$. Electrophilic addition of $Cl_2$ across the double bond in the presence of $CCl_4$ yields a vicinal dichlo

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(C) The reaction proceeds in two steps:$1$. Electrophilic addition of $Cl_2$ across the double bond in the presence of $CCl_4$ yields a vicinal dichloride: $CH_3O-C_6H_4-CH_2-CH_2-CHCl-CH_2Cl$.$2$. In the presence of anhydrous $AlCl_3$ (a Lewis acid),one of the chlorine atoms is abstracted to form a carbocation. The electron-rich benzene ring (activated by the $-OCH_3$ group) then undergoes intramolecular Friedel-Crafts alkylation.$3$. The cyclization occurs such that the more stable carbocation intermediate leads to the formation of a six-membered ring,resulting in $6-methoxy-2-chlorotetralin$ (or a related isomer depending on the specific cyclization pathway). Based on the provided options,the product is $C$.

The major product of the following reaction is

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The major product of the following reaction is:

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