The major product of the following reaction is: $CH_3-CH(Br)-CH_2-CH(Br)-CH_2-CH_3 \xrightarrow[heat]{KOH, CH_3OH}$

  • A
    $CH_2=CH-CH_2-CH=CH-CH_3$
  • B
    $CH_2=CH-CH=CH-CH_2-CH_3$
  • C
    $CH_3-CH=C=CH-CH_2-CH_3$
  • D
    $CH_3-CH=CH-CH=CH-CH_3$

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In the given reaction:
$CH_3-CH_2-\ddot{S}-CH_2^*-CH_2-Br \xrightarrow{HOH} [X]$
$[X]$ will be:

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