The major product of the following reaction is $CH_3CH=CHCO_2CH_3 \xrightarrow{LiAlH_4}$

  • A
    $CH_3CH_2CH_2CHO$
  • B
    $CH_3CH=CHCH_2OH$
  • C
    $CH_3CH_2CH_2CO_2CH_3$
  • D
    $CH_3CH_2CH_2CH_2OH$

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