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Question

(A) The reaction of the given substrate with $Br_2$ in the presence of $h
u$ (ultraviolet light) proceeds via a free-radical substitution mechanism.I

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) The reaction of the given substrate with $Br_2$ in the presence of $h
u$ (ultraviolet light) proceeds via a free-radical substitution mechanism.In this specific molecule,the allylic position (the carbon adjacent to the double bond in the ethyl group) is the most reactive site for radical bromination.Therefore,the bromine atom replaces one of the hydrogen atoms at the allylic position.The major product contains $1$ bromine atom.

The major product of the following reaction contains $.....$ bromine atom$(s)$.

Similar Questions

$A$ hydrocarbon with molecular formula $C_4H_6$ undergoes the following reactions:
$A$. Decolourises molecular bromine.
$B$. Reacts with $HBr$.
$C$. Addition of ozone and then cleavage of the ozonide by $Zn / H_2O$ gives the product $C_4H_6O_2$.
Then,the structure of the hydrocarbon is:

Among the following pairs,in which case does the second compound have a higher heat of hydrogenation?

The major product $A$ is:

The correct statement is

The conversion of cyclohexene to $HO-(CH_2)_6-OH$ can be achieved by:

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