The major product obtained on treatment of CH | vedclass

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(B) The reaction of $CH_3CH_2CH(F)CH_3$ with a strong base like $CH_3O^-$ in $CH_3OH$ proceeds via an $E2$ elimination mechanism.According to Saytzeff

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$CH_3CH=CHCH_3$

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(B) The reaction of $CH_3CH_2CH(F)CH_3$ with a strong base like $CH_3O^-$ in $CH_3OH$ proceeds via an $E2$ elimination mechanism.According to Saytzeff's rule,the more substituted alkene is the major product.Here,the base abstracts a proton from the $\beta$-carbon.Removing a proton from $C_3$ leads to $CH_3CH=CHCH_3$ (but$-2-$ene),which is more substituted and thus more stable.Removing a proton from $C_1$ leads to $CH_3CH_2CH=CH_2$ (but$-1-$ene),which is less substituted.Therefore,$CH_3CH=CHCH_3$ is the major product.

The major product obtained on treatment of $CH_3CH_2CH(F)CH_3$ with $CH_3O^-/CH_3OH$ is

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