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(A) The reaction of aniline $(C_6H_5NH_2)$ with acetic anhydride $(CH_3CO)_2O$ is an acetylation reaction. In this reaction,the lone pair of electrons

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(A) The reaction of aniline $(C_6H_5NH_2)$ with acetic anhydride $(CH_3CO)_2O$ is an acetylation reaction. In this reaction,the lone pair of electrons on the nitrogen atom of the aniline attacks the carbonyl carbon of the acetic anhydride. This leads to the formation of $N$-phenylethanamide,commonly known as acetanilide $(C_6H_5NHCOCH_3)$,and acetic acid $(CH_3COOH)$ as a byproduct. The reaction is: $C_6H_5NH_2 + (CH_3CO)_2O \rightarrow C_6H_5NHCOCH_3 + CH_3COOH$ Therefore,the major product is $N$-phenylethanamide.

The major product obtained in the reaction of aniline with acetic anhydride is

Similar Questions

Which of the following amines acts as the strongest base?

What is the correct order of basicity for the following compounds?
$1$. $C_6H_5NH_2$ (Aniline)
$2$. $CH_3CH_2NH_2$ (Ethylamine)
$3$. $(CH_3)_2NH$ (Dimethylamine)
$4$. $CH_3CONH_2$ (Acetamide)

Which of the following reactions will $NOT$ give a primary amine as the product?

The product $(A)$ is:

Which of the following products is obtained upon the hydrolysis of a primary amine?

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