The major product in the reaction is:

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(B) The reactant is benzene$-1,3-$dicarboxylic acid (isophthalic acid). Both $-COOH$ groups are strongly electron-withdrawing and meta-directing. In b

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$1,3-$dicarboxy$-5-$bromobenzene

Vedclass · Answer

(B) The reactant is benzene$-1,3-$dicarboxylic acid (isophthalic acid). Both $-COOH$ groups are strongly electron-withdrawing and meta-directing. In benzene$-1,3-$dicarboxylic acid,the positions $2, 4, 5,$ and $6$ are available for electrophilic substitution. Position $5$ is meta to both $-COOH$ groups. Electrophilic aromatic substitution (bromination) occurs at the position that is meta to both electron-withdrawing groups to minimize steric hindrance and electronic repulsion. Therefore,the major product is $5$-bromobenzene-$1,3$-dicarboxylic acid.

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