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(A) The reaction is a Nucleophilic Aromatic Substitution $(S_NAr)$ reaction.In $S_NAr$ reactions,the leaving group ability is determined by the electr

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$1-$piperidino$-2-$chloro$-4-$nitrobenzene

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(A) The reaction is a Nucleophilic Aromatic Substitution $(S_NAr)$ reaction.In $S_NAr$ reactions,the leaving group ability is determined by the electronegativity of the halogen atom because the rate-determining step is the formation of the Meisenheimer complex.Fluorine $(F)$ is more electronegative than Chlorine $(Cl)$,which makes the carbon atom attached to $F$ more electron-deficient and thus more susceptible to nucleophilic attack.Therefore,the nucleophile (piperidine) will preferentially displace the fluorine atom rather than the chlorine atom.The product formed is $1$-piperidino-$2$-chloro-$4$-nitrobenzene.

Column-$I$ (Reactants)	Column-$II$ (Products)
$(A)$ $p$-Nitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 443 \ K}$	$(i)$ Phenol
$(B)$ Chlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 623 \ K, 300 \ atm}$	$(ii)$ $2,4,6$-Trinitrophenol
$(C)$ $2,4$-Dinitrochlorobenzene $\xrightarrow[(ii) H^+]{(i) NaOH, 368 \ K}$	$(iii)$ $2,4$-Dinitrophenol
$(D)$ $2,4,6$-Trinitrochlorobenzene $\xrightarrow{Warm \ H_2O}$	$(iv)$ $p$-Nitrophenol

The main product of the following reaction will be
$1$-fluoro-$2$-chloro-$4$-nitrobenzene + piperidine $\to$ Product

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The main product of the following reaction will be$1$-fluoro-$2$-chloro-$4$-nitrobenzene + piperidine $\to$ Product