The magnitude of magnetic moment (spin only) | vedclass

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(A) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.Since $Cl^-$ is a weak field ligan

Vedclass · Accepted Answer

$2.82$

Vedclass · Answer

(A) In $[NiCl_4]^{2-}$,the oxidation state of $Ni$ is $+2$.The electronic configuration of $Ni^{2+}$ is $[Ar] 3d^8$.Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals.Thus,there are $2$ unpaired electrons in the $3d$ subshell.The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.For $n = 2$,$\mu = \sqrt{2(2+2)} = \sqrt{8} \approx 2.82 \ B.M.$

The magnitude of magnetic moment (spin only) of $[NiCl_4]^{2-}$ will be ........ $B.M.$

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