The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by
The magnitude of electric field intensity $E$ is such that, an electron placed in it would experience an electrical force equal to its weight is given by
- A
$mge$
- B
$\frac{{mg}}{e}$
- C
$\frac{e}{{mg}}$
- D
$\frac{{{e^2}}}{{{m^2}}}g$
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- [JEE MAIN 2021]
Explain electric field and also electric field by point charge.
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