The magnetization of a bar magnet of length $5 \ cm$,cross-sectional area $2 \ cm^2$ and net magnetic moment $1 \ A \cdot m^2$ is:

If $M$ is the magnetisation induced in the material,$H$ is the magnetic field intensity,and $B$ is the net magnetic field inside the material,then the correct relation between them is $(\mu_0 = \text{permeability of free space})$

An iron rod of susceptibility $599$ is subjected to a magnetising field of $1200 \, A m^{-1}$. The permeability of the material of the rod is $(\mu_{0} = 4 \pi \times 10^{-7} \, T m A^{-1})$.

An iron rod of cross-sectional area $2 \times 10^{-5} \ m^2$ is subjected to a magnetizing field intensity of $2000 \ A/m$. If the magnetic flux produced in the rod is $6.28 \times 10^{-4} \ Wb$,what is the magnetic permeability of the rod?

An iron rod is placed parallel to a magnetic field of intensity $2000 \text{ A/m}$. The magnetic flux through the rod is $6 \times 10^{-4} \text{ Wb}$ and its cross-sectional area is $3 \text{ cm}^2$. The magnetic permeability of the rod in $\text{Wb/(A} \cdot \text{m)}$ is:

By putting a magnetic substance of volume $30\, cm^3$ in a magnetising field of strength $\frac{1250}{\pi} \, A/m$,the value of the produced magnetic moment is $6\, A\cdot m^2$. Calculate the value of magnetic induction produced in the substance in $T$.