(B) In a tangent galvanometer,the magnetic field $B_{m}$ produced by the coil (or magnet) is perpendicular to the horizontal component of the earth's

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$1.96 \times 10^{-5} \text{ T}$

(B) In a tangent galvanometer,the magnetic field $B_{m}$ produced by the coil (or magnet) is perpendicular to the horizontal component of the earth's magnetic field $B_{H}$.The deflection $\theta$ is given by the tangent law: $B_{m} = B_{H} \tan \theta$.Given:$B_{H} = 0.34 \times 10^{-4} \text{ T}$$\theta = 30^{\circ}$Substituting the values:$B_{m} = (0.34 \times 10^{-4}) \times \tan 30^{\circ}$$B_{m} = (0.34 \times 10^{-4}) \times \frac{1}{\sqrt{3}}$$B_{m} = \frac{0.34 \times 10^{-4}}{1.732}$$B_{m} \approx 0.1963 \times 10^{-4} \text{ T}$$B_{m} \approx 1.96 \times 10^{-5} \text{ T}$

Class 12 Physics Magnetism and Matter Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

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The magnetic needle of a tangent galvanometer is deflected at an angle $30^{\circ}$ due to a magnet. The horizontal component of the earth's magnetic field is $0.34 \times 10^{-4} \text{ T}$,which is along the plane of the coil. The magnetic field due to the magnet is:

A
$1.96 \times 10^{-4} \text{ T}$
B
$1.96 \times 10^{-5} \text{ T}$
C
$1.96 \times 10^{4} \text{ T}$
D
$1.96 \times 10^{5} \text{ T}$

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Magnetic Equipment's (Tangent galvanometer, Vibration magnetometer and Neutral point)

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The magnetic needle of a tangent galvanometer is deflected at an angle $30^{\circ}$ due to a magnet. The horizontal component of the earth's magnetic field is $0.34 \times 10^{-4} \text{ T}$,which is along the plane of the coil. The magnetic field due to the magnet is:

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$A$ short magnet of magnetic moment $6.75 \, Am^2$ produces a neutral point on its axis. If the horizontal component of the Earth's magnetic field is $5 \times 10^{-5} \, Wb/m^2$, then the distance of the neutral point from the center of the magnet is.....$cm$.

$A$ bar magnet is oscillating in the earth's magnetic field with a time period $T$. If a similar magnet with the same mass and volume has a magnetic dipole moment which is $9$ times that of this magnet,then its time period will be . . . . . . .

$A$ short bar magnet with its north pole facing north forms a neutral point at $P$ in the horizontal plane. If the magnet is rotated by $90^o$ in the horizontal plane,the net magnetic induction at $P$ is (Horizontal component of earth's magnetic field = $B_H$)

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