(C) The magnetic moment $m$ of a current-carrying coil is given by $m = N I A$,where $N$ is the number of turns,$I$ is the current,and $A$ is the area

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The magnetic moment $m$ of a current-carrying coil is given by $m = N I A$,where $N$ is the number of turns,$I$ is the current,and $A$ is the area of the coil.Given that the magnetic moments of coils $A$ and $B$ are equal,$m_A = m_B$.Therefore,$N_A I_A A_A = N_B I_B A_B$.Since the coils are circular,the area $A = \pi r^2$. Thus,$N_A I_A (\pi r_A^2) = N_B I_B (\pi r_B^2)$.Substituting the given radii $r_A = 10 \ cm$ and $r_B = 20 \ cm$:$N_A I_A (10)^2 = N_B I_B (20)^2$.$N_A I_A (100) = N_B I_B (400)$.$N_A I_A = 4 \ N_B I_B$.

Class 12 Physics Moving Charges and Magnetism Magnetic Moment of Current Carrying Coil

Easy

The magnetic moments associated with two closely wound circular coils $A$ and $B$ of radius $r_A = 10 \ cm$ and $r_B = 20 \ cm$ respectively are equal. If $N_A, I_A$ and $N_B, I_B$ are the number of turns and current of $A$ and $B$ respectively,then which of the following relations is correct?

MHT CET 2024 All MHT CET

A
$2 \ N_A I_A = N_B I_B$
B
$N_A = 2 \ N_B$
C
$N_A I_A = 4 \ N_B I_B$
D
$4 \ N_A I_A = N_B I_B$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Moving Charges and Magnetism

Subtopic

Magnetic Moment of Current Carrying Coil

Previous Year

MHT CET 2024 Paper All MHT CET years →

The dipole moment of a circular loop carrying a current $I$ is $m$ and the magnetic field at the centre of the loop is $B_1$. When the dipole moment is doubled by keeping the current constant,the magnetic field at the centre of the loop is $B_2$. The ratio $\frac{B_1}{B_2}$ is

MediumJEE MAIN 2018

View Solution

The magnetic field at the centre of a current carrying circular coil of an area $A$ is $B$. The magnetic moment of the coil is (where $\mu_0$ is the permeability of free space).

DifficultMHT CET 2022

View Solution

$A$ wire carrying current $I$ is bent in the shape $A, B, C, D, E, F, A$ as shown,where rectangle $A, B, C, D, A$ and $A, D, E, F, A$ are perpendicular to each other. If the sides of the rectangles are of lengths $a$ and $b$,then the magnitude and direction of the magnetic moment of the loop $A, B, C, D, E, F, A$ is

DifficultJEE MAIN 2020

View Solution

An electron moves in a circular orbit with a uniform speed $v$. It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

MediumAIPMT 2005

View Solution

$A$ thin circular disk of radius $R$ is uniformly charged with surface charge density $\sigma > 0$. The disk rotates about its central axis with a uniform angular speed $\omega$. The magnetic moment of the disk is:

DifficultAIEEE 2011

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The magnetic moments associated with two closely wound circular coils $A$ and $B$ of radius $r_A = 10 \ cm$ and $r_B = 20 \ cm$ respectively are equal. If $N_A, I_A$ and $N_B, I_B$ are the number of turns and current of $A$ and $B$ respectively,then which of the following relations is correct?

Similar Questions

The dipole moment of a circular loop carrying a current $I$ is $m$ and the magnetic field at the centre of the loop is $B_1$. When the dipole moment is doubled by keeping the current constant,the magnetic field at the centre of the loop is $B_2$. The ratio $\frac{B_1}{B_2}$ is

The magnetic field at the centre of a current carrying circular coil of an area $A$ is $B$. The magnetic moment of the coil is (where $\mu_0$ is the permeability of free space).

An electron moves in a circular orbit with a uniform speed $v$. It produces a magnetic field $B$ at the centre of the circle. The radius of the circle is proportional to

$A$ thin circular disk of radius $R$ is uniformly charged with surface charge density $\sigma > 0$. The disk rotates about its central axis with a uniform angular speed $\omega$. The magnetic moment of the disk is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module