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(D) The intensity of magnetization $M$ is defined as the magnetic moment per unit volume.$M = \frac{m_{net}}{V}$Given mass $m = 5 \ g$ and density $\r

Vedclass · Accepted Answer

$0.6$

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(D) The intensity of magnetization $M$ is defined as the magnetic moment per unit volume.$M = \frac{m_{net}}{V}$Given mass $m = 5 \ g$ and density $ho = 5 \ g/cm^{3}$.Volume $V = \frac{m}{ho} = \frac{5 \ g}{5 \ g/cm^{3}} = 1 \ cm^{3}$.Convert volume to $SI$ units: $1 \ cm^{3} = 10^{-6} \ m^{3}$.Given magnetic moment $m_{net} = 6 	imes 10^{-7} \ A \cdot m^{2}$.$M = \frac{6 	imes 10^{-7} \ A \cdot m^{2}}{10^{-6} \ m^{3}} = 6 	imes 10^{-1} \ A/m = 0.6 \ A/m$.Therefore,the correct option is $D$.

The magnetic moment produced in a substance of mass $5 \ g$ is $6 \times 10^{-7} \ A \cdot m^{2}$. If its density is $5 \ g/cm^{3}$,then the intensity of magnetization in $A/m$ will be:

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