The magnetic flux through a coil perpendicular to its plane is varying according to the relation $\phi = (5t^3 + 4t^2 + 2t - 5) \; Wb$. If the resistance of the coil is $5 \; \Omega$,then the induced current through the coil at $t = 2 \; s$ will be $.... \; A$. (in $.6$)
- A$15$
- B$16$
- C$17$
- D$18$
Explore More
Similar Questions
$A$ magnet is moved towards a stationary coil with speed $V$. The induced e.m.f. in the coil is $e$. If the magnet and the coil move away from one another,each moving with speed $V$,then the induced e.m.f. in the coil is:
Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.
Reason $(R):$ Clockwise current is induced in the coil.
MediumAIIMS 2015
View Solution$A$ coil of resistance $16 \Omega$ is placed with its plane perpendicular to a uniform magnetic field whose flux ($\phi$ in $10^{-3} \text{ Wb}$) changes with time ($t$ in seconds) as $\phi = 5t^2 + 4t + 2$. The induced current at time $t = 6 \text{ s}$ is: (in $\text{ mA}$)
Magnetic flux linked with the coil is given by $\phi(t) = 2t^2 + 2t + 1$ and its resistance is $10 \ \Omega$. The current passing through the coil at $t = 2 \ s$ is . . . . . . $A$.
$A$ coil having effective area $A$ is held with its plane normal to a magnetic field of induction $B$. The magnetic induction is quickly reduced by $25 \%$ of its initial value in $2 \ s$. The e.m.f. induced across the coil will be:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo