The magnetic field (B) inside a long solenoid | vedclass

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Question

(D) The magnetic field inside a long solenoid with an air core is given by $B_0 = \mu_0 n I$.When a magnetic material with magnetic susceptibility $\c

Vedclass · Accepted Answer

$\mu_0 n I (1 + \chi)$

Vedclass · Answer

(D) The magnetic field inside a long solenoid with an air core is given by $B_0 = \mu_0 n I$.When a magnetic material with magnetic susceptibility $\chi$ is placed inside the solenoid,the total magnetic field $B$ is the sum of the field due to the current and the field due to the magnetization of the material.The magnetization $M$ is given by $M = \chi H$,where $H = n I$ is the magnetic intensity.The total magnetic field is $B = \mu_0 (H + M) = \mu_0 (H + \chi H) = \mu_0 H (1 + \chi)$.Substituting $H = n I$,we get $B = \mu_0 n I (1 + \chi)$.

The magnetic field $(B)$ inside a long solenoid having $n$ turns per unit length and carrying current $I$ when an iron core is kept in it is ($\mu_0 = $ permeability of vacuum,$\chi = $ magnetic susceptibility).

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