The logic gate equivalent to the circuit give | vedclass

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Question

(A) Let the inputs be $A$ and $B$.Each input passes through a $NOT$ gate,so the inputs to the first stage $NAND$ gates become $\bar{A}$ and $\bar{B}$.

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$NAND$

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(A) Let the inputs be $A$ and $B$.Each input passes through a $NOT$ gate,so the inputs to the first stage $NAND$ gates become $\bar{A}$ and $\bar{B}$.Since both inputs of the first stage $NAND$ gates are tied together,they act as $NOT$ gates. Thus,the outputs of the first stage are $\overline{\bar{A}} = A$ and $\overline{\bar{B}} = B$.These outputs $A$ and $B$ are then fed into the final $NAND$ gate.The output of the final $NAND$ gate is $Y = \overline{A \cdot B}$.This is the Boolean expression for a $NAND$ gate.Therefore,the circuit is equivalent to a $NAND$ gate.

The logic gate equivalent to the circuit given in the figure is

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