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(D) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$.The outputs of the two $NOT$ gates are $\bar{

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(D) The given circuit consists of two $NOT$ gates followed by a $NOR$ gate.Let the inputs be $A$ and $B$.The outputs of the two $NOT$ gates are $\bar{A}$ and $\bar{B}$.These are fed into a $NOR$ gate,so the final output $Y$ is given by:$Y = \overline{\bar{A} + \bar{B}}$Using De Morgan's theorem,$\overline{\bar{A} + \bar{B}} = \overline{(\bar{A})} \cdot \overline{(\bar{B})} = A \cdot B$.Thus,the circuit acts as an $AND$ gate.The output $Y$ is high $(1)$ only when both inputs $A$ and $B$ are high $(1)$.By observing the input waveforms,the output waveform will be high only during the time interval where both $A$ and $B$ are high.

The logic circuit shown below has the input waveforms $A$ and $B$ as shown. Pick out the correct output waveform.

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