The lines 2x + 3y = 6 and 2x + 3y = 8 cut the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given lines are $2x + 3y = 6$ and $2x + 3y = 8$. These lines meet the $X$-axis at $A(3, 0)$ and $B(4, 0)$ respectively. The line $L$ passes throug

Vedclass · Accepted Answer

$2x + 3y = 10$

Vedclass · Answer

(A) Given lines are $2x + 3y = 6$ and $2x + 3y = 8$. These lines meet the $X$-axis at $A(3, 0)$ and $B(4, 0)$ respectively. The line $L$ passes through $(2, 2)$ and cuts the $X$-axis at $C(x_1, 0)$,such that the $x$-coordinates of $A, B,$ and $C$ are in arithmetic progression,i.e.,$3, 4, x_1$. Since they are in arithmetic progression,$2 	imes 4 = 3 + x_1$,which gives $x_1 = 8 - 3 = 5$. So,the coordinates of $C$ are $(5, 0)$. $A$ line $L$ passing through the points $(2, 2)$ and $(5, 0)$ is given by: $y - 0 = \frac{0 - 2}{5 - 2}(x - 5)$ $y = \frac{-2}{3}(x - 5)$ $3y = -2x + 10$ $2x + 3y = 10$

The lines $2x + 3y = 6$ and $2x + 3y = 8$ cut the $X$-axis at $A$ and $B$,respectively. $A$ line $L$ drawn through the point $(2, 2)$ meets the $X$-axis at $C$ in such a way that the abscissae of $A, B,$ and $C$ are in arithmetic progression. Then,the equation of the line $L$ is

Similar Questions

The major product in the following reaction is:

$A$ solution of sodium sulphate contains $92 \ g$ of $Na^{+}$ ions per kilogram of water. The molality of $Na^{+}$ ions in that solution in $mol \ kg^{-1}$ is:

What is $Strigula$?

$A$ line is at a constant distance $c$ from the origin and meets the coordinate axes in $A$ and $B$. The locus of the centre of the circle passing through $O, A, B$ is

If $z = \frac{y}{x} \left[ \sin \frac{x}{y} + \cos \left( 1 + \frac{y}{x} \right) \right]$,then $x \frac{\partial z}{\partial x}$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module