The lengths of the diagonals of a rhombus are | vedclass

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(B) Let the rhombus be $ABCD$ with diagonals $d_1 = 10$ and $d_2 = 24$.In a rhombus,the diagonals bisect each other at right angles $(90^{\circ})$.Let

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$13$

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(B) Let the rhombus be $ABCD$ with diagonals $d_1 = 10$ and $d_2 = 24$.In a rhombus,the diagonals bisect each other at right angles $(90^{\circ})$.Let the diagonals intersect at point $O$. Then,the segments of the diagonals are $d_1/2 = 5$ and $d_2/2 = 12$.These segments form a right-angled triangle with the side of the rhombus as the hypotenuse.Using the Pythagorean theorem: $side^2 = (d_1/2)^2 + (d_2/2)^2$.$side^2 = 5^2 + 12^2 = 25 + 144 = 169$.$side = \sqrt{169} = 13$.Therefore,the length of each side of the rhombus is $13$.

The lengths of the diagonals of a rhombus are $10$ and $24$. Then,the length of each side of the rhombus is $\ldots \ldots \ldots \ldots . .$

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