The length of the seconds pendulum is decreased by $0.3 \ cm$ when it is shifted from place $A$ to place $B$. If the acceleration due to gravity at place $A$ is $981 \ cm/s^2$,the acceleration due to gravity at place $B$ is $($ Take $\pi^2 = 10$ $)$ (in $cm/s^2$)

$A$ simple pendulum oscillates in a vertical plane. When it passes through the mean position,the tension in the string is $3$ times the weight of the pendulum bob. What is the maximum displacement of the pendulum string with respect to the vertical in degrees?

The period of small oscillation of a simple pendulum is $T$. The ratio of the density of the liquid to the density of the material of the bob is $\rho$ (where $\rho < 1$). When the bob is immersed in the liquid,the new time period of small oscillation will be:

$A$ simple pendulum is suspended from the ceiling of a lift. When the lift is at rest,its time period is $T$. With what acceleration should the lift be accelerated upwards in order to reduce its period to $T/2$ (in $g$)? ($g$ is acceleration due to gravity).

$A$ simple pendulum is suspended in a lift which is going up with an acceleration $5 \ m/s^2$. An electric field of magnitude $5 \ N/C$ and directed vertically upward is also present in the lift. The charge of the bob is $1 \ mC$ and mass is $1 \ mg$. Taking $g = \pi^2 \ m/s^2$ and length of the simple pendulum $1 \ m$,the time period of the simple pendulum is ...... $s$.

Two simple pendulums whose lengths are $100 \ cm$ and $121 \ cm$ are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum,will the two be in phase again?