The length of an arc which subtends an angle | vedclass

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(C) The formula for the length of an arc $l$ is given by $l = r	heta$,where $r$ is the radius and $	heta$ is the angle in radians.Given radius $r =

Vedclass · Accepted Answer

$\frac{3\pi}{5}$

Vedclass · Answer

(C) The formula for the length of an arc $l$ is given by $l = r	heta$,where $r$ is the radius and $	heta$ is the angle in radians.Given radius $r = 6 	ext{ cm}$ and angle $	heta = 18^{\circ}$.First,convert the angle from degrees to radians: $	heta = 18^{\circ} 	imes \frac{\pi}{180^{\circ}} = \frac{\pi}{10} 	ext{ radians}$.Now,substitute the values into the formula: $l = 6 	imes \frac{\pi}{10} = \frac{6\pi}{10} = \frac{3\pi}{5} 	ext{ cm}$.Thus,the correct option is $C$.

The length of an arc which subtends an angle $18^{\circ}$ at the centre of the circle of radius $6 \text{ cm}$ is (in $\text{cm}$)

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