The length of a rectangular plot is 60% more | vedclass

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Question

(C) Let the breadth of the rectangle be $x\, cm$.According to the problem,the length is $60\%$ more than the breadth,so the length is $x + 0.60x = 1.6

Vedclass · Accepted Answer

$2560$

Vedclass · Answer

(C) Let the breadth of the rectangle be $x\, cm$.According to the problem,the length is $60\%$ more than the breadth,so the length is $x + 0.60x = 1.6x\, cm$.The difference between the length and the breadth is given as $24\, cm$.Therefore,$1.6x - x = 24$.$0.6x = 24$.$x = \frac{24}{0.6} = 40\, cm$.Thus,the breadth is $40\, cm$ and the length is $1.6 	imes 40 = 64\, cm$.The area of the rectangle is $	ext{length} 	imes 	ext{breadth} = 64 	imes 40 = 2560\, cm^2$.

The length of a rectangular plot is $60\%$ more than its breadth. If the difference between the length and the breadth of that rectangle is $24\, cm$,what is the area of that rectangle? (in $cm^2$)

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