The length of a rectangular garden exceeds it | vedclass

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(B) Let the breadth of the rectangular garden be $x \, m$.Then,the length of the garden is $(x + 6) \, m$.The area of the rectangle is given by $	ext

Vedclass · Accepted Answer

length $: 18 \, m, 	ext{ breadth } : 12 \, m$

Vedclass · Answer

(B) Let the breadth of the rectangular garden be $x \, m$.Then,the length of the garden is $(x + 6) \, m$.The area of the rectangle is given by $	ext{length} 	imes 	ext{breadth} = 216 \, m^2$.So,$x(x + 6) = 216$.$x^2 + 6x - 216 = 0$.To solve this quadratic equation,we factorize it: $x^2 + 18x - 12x - 216 = 0$.$x(x + 18) - 12(x + 18) = 0$.$(x - 12)(x + 18) = 0$.Since the breadth cannot be negative,we take $x = 12$.Thus,the breadth is $12 \, m$ and the length is $12 + 6 = 18 \, m$.

The length of a rectangular garden exceeds its breadth by $6 \, m$. If the area of the garden is $216 \, m^2$,find the length and the breadth of the garden.

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