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(A) The total length of $DNA$ in $E. coli$ is calculated by multiplying the total number of base pairs by the distance between two consecutive base pa

Vedclass · Accepted Answer

$1.36 \ mm$

Vedclass · Answer

(A) The total length of $DNA$ in $E. coli$ is calculated by multiplying the total number of base pairs by the distance between two consecutive base pairs.$E. coli$ has $4.6 	imes 10^6$ base pairs.The distance between two consecutive base pairs is $0.34 	imes 10^{-9} \ m$.Length = $(4.6 	imes 10^6) 	imes (0.34 	imes 10^{-9} \ m) \approx 1.36 	imes 10^{-3} \ m = 1.36 \ mm$.Therefore,the correct option is $A$.

The length of $DNA$ in $E. coli$ is . . . . . . .

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