The largest 4-digit integer divisible by 95 i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The largest $4$-digit number is $9999$.To find the largest $4$-digit number divisible by $95$,we divide $9999$ by $95$.$9999 \div 95 = 105$ with a

Vedclass · Accepted Answer

$9985$

Vedclass · Answer

(C) The largest $4$-digit number is $9999$.To find the largest $4$-digit number divisible by $95$,we divide $9999$ by $95$.$9999 \div 95 = 105$ with a remainder.$9999 = 95 	imes 105 + 14$.The remainder is $14$.To find the largest $4$-digit number divisible by $95$,we subtract the remainder from the largest $4$-digit number:$9999 - 14 = 9985$.Thus,$9985$ is the largest $4$-digit integer divisible by $95$.

The largest $4$-digit integer divisible by $95$ is . . . . . . .

Similar Questions

Find the Least Common Multiple $(LCM)$ of $6$,$72$,and $120$.

If $HCF(a, b) = 12$,then which of the following cannot be the $LCM(a, b)$? Options: $(A) 90, (B) 24, (C) 48, (D) 60$.

For any positive integer $n$,the last digit of $5^n$ is always.......

The Least Common Multiple $(LCM)$ of the smallest prime number and the smallest composite number is . . . . . . .

If $a, b, c$ are distinct prime integers,then the ratio of their $HCF$ to their $LCM$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module