The lanthanoid that would show color is

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(D) The color of lanthanoid ions depends on the presence of unpaired $f$-electrons. $La^{3+}$ has a configuration of $[Xe] 4f^0$ (no unpaired electron

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$Sm^{3+}$

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(D) The color of lanthanoid ions depends on the presence of unpaired $f$-electrons. $La^{3+}$ has a configuration of $[Xe] 4f^0$ (no unpaired electrons). $Gd^{3+}$ has a configuration of $[Xe] 4f^7$ (half-filled,stable,but colorless in many compounds due to high energy transition). $Lu^{3+}$ has a configuration of $[Xe] 4f^{14}$ (fully filled,no unpaired electrons). $Sm^{3+}$ has a configuration of $[Xe] 4f^5$,which contains unpaired electrons,allowing for $f-f$ transitions that result in a yellow color.

Similar Questions

Compare the chemistry of the actinoids with that of lanthanoids with reference to:
$(i)$ electronic configuration
$(ii)$ oxidation states and
$(iii)$ chemical reactivity.

Which of the following lanthanoids exhibits no effective magnetic moment in the $+3$ oxidation state?

Explain the size of actinoid elements and their ions.

The lanthanide for which $+II$ and $+III$ oxidation states are common is:

What is the highest oxidation state exhibited by actinoids?

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