The isostructural molecules among CO_2, SiO_2 | vedclass

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Question

(C) To determine isostructural molecules,we check the hybridization and geometry of the central atom: $CO_2$: The central $C$ atom is $sp$-hybridized,

Vedclass · Accepted Answer

$CO_2, [NO_2]^{+}$

Vedclass · Answer

(C) To determine isostructural molecules,we check the hybridization and geometry of the central atom: $CO_2$: The central $C$ atom is $sp$-hybridized,resulting in a linear geometry. $[NO_2]^{+}$: The central $N$ atom is $sp$-hybridized,resulting in a linear geometry. $SiO_2$: Exists as a giant covalent network (quartz) with $sp^3$ hybridization. $SO_2$ and $TeO_2$: Both have $sp^2$ hybridization with one lone pair,resulting in a bent (angular) geometry. Since both $CO_2$ and $[NO_2]^{+}$ are linear,they are isostructural. Thus,the correct option is $C$.

List-$I$	List-$II$
$(a)$ $PCl_{5}$	$(i)$ Square pyramidal
$(b)$ $SF_{6}$	$(ii)$ Trigonal planar
$(c)$ $BrF_{5}$	$(iii)$ Octahedral
$(d)$ $BF_{3}$	$(iv)$ Trigonal bipyramidal

The isostructural molecules among $CO_2, SiO_2, SO_2, TeO_2, [NO_2]^{+}$ are

Similar Questions

Match List-$I$ with List-$II$.

List-$I$ List-$II$

$(a)$ $PCl_{5}$ $(i)$ Square pyramidal

$(b)$ $SF_{6}$ $(ii)$ Trigonal planar

$(c)$ $BrF_{5}$ $(iii)$ Octahedral

$(d)$ $BF_{3}$ $(iv)$ Trigonal bipyramidal

Choose the correct answer from the options given below.

In the following reaction,how do the $Cl-P-Cl$ bond angles change?
$PCl_5 \longrightarrow PCl_4^+ + Cl^-$

The molecular shapes of $SF_4$,$CF_4$,and $XeF_4$ are

Which of the following molecules does not have a lone pair of electrons in the valence shell of the central atom?

Which of the following has a pyramidal structure?

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