The isoelectronic pair is

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(C) Isoelectronic species are those that have the same number of electrons.Let us calculate the total number of electrons for each pair:$(A) \ CO, N_2

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$CO, N_2$ and $F_2, HCl$

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(C) Isoelectronic species are those that have the same number of electrons.Let us calculate the total number of electrons for each pair:$(A) \ CO, N_2$: $CO = 6 + 8 = 14$; $N_2 = 7 + 7 = 14$. (Isoelectronic)$(B) \ O_2, NO$: $O_2 = 8 + 8 = 16$; $NO = 7 + 8 = 15$. (Not isoelectronic)$(D) \ F_2, HCl$: $F_2 = 9 + 9 = 18$; $HCl = 1 + 17 = 18$. (Isoelectronic)Since both $(A)$ and $(D)$ represent isoelectronic pairs,the correct choice is $(C)$.

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