The ionisation constant of phenol is higher than that of ethanol because

What will be the product $X$ in the following reaction?

The reactant is $4-hydroxy-3-methylbenzenesulfonic acid$. The reaction with $Br_2$ in $H_2O$ (bromine water) is an electrophilic aromatic substitution. The $-OH$ group is strongly activating and ortho/para directing. The $-SO_3H$ group is a good leaving group in the presence of excess bromine water. Predict the product of the reaction: $\xrightarrow{Br_2, H_2O} \text{Product}$

The reaction of phenol with chloroform and sodium hydroxide to give $o$-hydroxybenzaldehyde involves the formation of which intermediate?

When phenol reacts with dilute nitric acid at room temperature,the major product obtained is

Which of the following is strongly acidic?