The ionic radii of Li^{+},Be^{2+},and B^{3+} | vedclass

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Question

(D) The ions $Li^{+}$,$Be^{2+}$,and $B^{3+}$ are isoelectronic species,all having the same number of electrons ($2$ electrons).For isoelectronic speci

Vedclass · Accepted Answer

$Li^{+} > Be^{2+} > B^{3+}$

Vedclass · Answer

(D) The ions $Li^{+}$,$Be^{2+}$,and $B^{3+}$ are isoelectronic species,all having the same number of electrons ($2$ electrons).For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.The atomic numbers are: $Li$ $(Z=3)$,$Be$ $(Z=4)$,and $B$ $(Z=5)$.Since the nuclear charge increases in the order $Li^{+} Therefore,the correct order of ionic radii is $Li^{+} > Be^{2+} > B^{3+}$.Hence,option $D$ is correct.

The ionic radii of $Li^{+}$,$Be^{2+}$,and $B^{3+}$ follow the order:

Similar Questions

From the given set of species,point out the species from each set having the least atomic/ionic radius:
$(A)$ $F^{-}, Na^{+}, Mg^{+2}$
$(B)$ $Ni, Cu, Zn$
$(C)$ $N^{-3}, Cs^{+}, H^{-}$
$(D)$ $Li, Li^{+}, Be^{+2}$

Which has the highest value of ionic radius?

What is atomic radius in reality?

Which of the following arrangements is correct regarding the three types of radii for an atom?

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