The ionic radii $(\mathring{A})$ of $C^{4-}$ and $O^{2-}$ respectively are $2.60$ and $1.40$. The ionic radius of the isoelectronic ion $N^{3-}$ would be........$\mathring{A}$

  • A
    $1.31$
  • B
    $2.83$
  • C
    $1.71$
  • D
    $2.63$

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