The interionic distance for $Cesium$ $chloride$ $(CsCl)$ crystal will be (where $a$ is the edge length of the unit cell):

  • A
    $a$
  • B
    $\frac{a}{2}$
  • C
    $\frac{\sqrt{3} a}{2}$
  • D
    $\frac{2a}{\sqrt{3}}$

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